$ 0 0 Hi, Try the below. I hope it will give you expected result sel emialtext,substr(emailtext,index(emailtext,'.')) from sch.table where emailtext like '%.%' Venkat
Hi,
Try the below. I hope it will give you expected result
sel emialtext,substr(emailtext,index(emailtext,'.')) from sch.table where emailtext like '%.%'
Venkat