Whom can help me explain the ‘46.06:18:08’ time. - response (5) by joop_kpn

all SQL college's,

Thanks for the response, I have changed my procedure to make use of time instead of integer presented as time "lesson learned" THX. And Dieter, you’re right, I'm working from a windows client using SQLA wit which is connected by ODBC to the database.
Opening an incident is another chapter, it would be my first and at this moment i don't have a clue how to do this.

Joop