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Average of volume by weekday and hour over range - response (2) by Dolm

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Thank you Dieter! I wound up using the calendar to divide by the the number of days in the date range, rather than only days with data. You've helped me tremendously!
 

SELECT
dt.dayofweek,
calls."hour",
 cast(calls.CountbyDayofWeek as decimal(15,3)) / dt.num_of_days as AVG_COUNT
 from

 (select 
       CASE   day_of_week
            WHEN 1 THEN 'Sun'            WHEN 2 THEN 'Mon'            WHEN 3 THEN 'Tue'            WHEN 4 THEN 'Wed'            WHEN 5 THEN 'Thu'            WHEN 6 THEN 'Fri'            WHEN 7 THEN 'Sat'        END as DayofWeek, 
       count(*) as num_of_days 
from sys_calendar.calendar 
where calendar_date Between '2013-03-07' AND '2013-05-07'
group by 1 
)dt
join

(SELECT
 EXTRACT(HOUR FROM case_creation_ts) AS "hour" ,
Count (*) as CountbyDayofWeek,  
CASE ((cast(case_creation_ts as date) - Date '1900-01-01') Mod 7) +1
WHEN 7 THEN 'Sun'
WHEN 1 THEN 'Mon'
WHEN 2 THEN 'Tue'
WHEN 3 THEN 'Wed'
WHEN 4 THEN 'Thu'
WHEN 5 THEN 'Fri'
WHEN 6 THEN 'Sat' END as DayofWeek 
FROM calls_table 
 Group by 1,3
 )calls on dt.dayofweek = calls.dayofweek
 
order by 1,2

I used the suggestion from Ulrich in a previous post, from: 
http://forums.teradata.com/forum/database/determine-average-count-by-day-of-week
 


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